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calculate the atomic Rb-87/Sr-86 ratio of a rock sample containing Rb=125 microg/g and Sr=275 microg/g.

Atomic weights: Rb=85.46, Sr=87.62

isotopic abundancy: Rb-87=27.83%, Sr-86=9.90%

I found the following formula:

Sr-87/Sr-86 = (Sr-87/Sr-86) small 0 + Rb-87/Sr-86 (e^labda*t -1)

Well, what do I do with this formular and how do I put all the given data into it?

Thousand thanks!

Martine