- #1
martine
- 27
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Please help me with this calculation. I read that chapter in my book three times now and still don't know what actually do to
calculate the atomic Rb-87/Sr-86 ratio of a rock sample containing Rb=125 microg/g and Sr=275 microg/g.
Atomic weights: Rb=85.46, Sr=87.62
isotopic abundancy: Rb-87=27.83%, Sr-86=9.90%
I found the following formula:
Sr-87/Sr-86 = (Sr-87/Sr-86) small 0 + Rb-87/Sr-86 (e^labda*t -1)
Well, what do I do with this formula and how do I put all the given data into it?
Thousand thanks!
Martine
calculate the atomic Rb-87/Sr-86 ratio of a rock sample containing Rb=125 microg/g and Sr=275 microg/g.
Atomic weights: Rb=85.46, Sr=87.62
isotopic abundancy: Rb-87=27.83%, Sr-86=9.90%
I found the following formula:
Sr-87/Sr-86 = (Sr-87/Sr-86) small 0 + Rb-87/Sr-86 (e^labda*t -1)
Well, what do I do with this formula and how do I put all the given data into it?
Thousand thanks!
Martine