# DB difference, intensity

## Homework Statement

Two sounds differ in sound level by 2.80 dB. By what factor is the one intensity greater than the other?

## The Attempt at a Solution

Is the equation

$$B$$ = 10dB log(I/Io)

relevant?

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rl.bhat
Homework Helper
The equation is
Bdb = 10log(I/Io)
Now let B1 = 10log(I1/Io) and
B2 = 10log(I2/Io)
Take the difference and find the ratio of I1/I2.

danago
Gold Member
Lets say sound 1 has an intensity of I1 and intensity level B, and sound 2 has an intensity of I2 with intensity level B+2.8

B = 10 log (I1 / I0)
B+2.8 = 10 log (I2 / I0)

See if you can use those

EDIT: rl.bhat beat me to it :P

I'm sorry, but the algebra is confusing me. Could you show the first few steps, please?

rl.bhat
Homework Helper
B1 = 10log(I1/Io)
B2 = 10log(I2/Io)
B1 -B2 = 10[log(I1/Io) - log(I2/Io)]
Use laws of logarithm to further simplification.