I'm having trouble solving this problem:(adsbygoogle = window.adsbygoogle || []).push({});

Three resistors(parallel) across a DC voltage source...If the total current through the circuit is I = 2.0A, what is the currect through the 12ohm resistor?

The circuit runs into a junction which splits 3 ways. Along each path there's are resistors 2ohm, 6ohm, and 12ohm, respectively, and all meet again andthen flows back to the battery.

It's parallel so I breaks up into I1, I2,I3

I found two equations:

8/3V = I1(2ohm) + I2(6ohm) + I3(12ohm)

I = I1 + I2 + I3

I found the voltage by first find the equivalent resistor for R1, R2, and R3, (R = 4/3 ohm) So V = IR => V = 2(4/3) => V = 8/3V.

I need to find the current through R3, and I could if I had one more equation, but I'm stuck. I can't see any other equations by loop rule or Kirchoff's law. So, any help will be appreciated, thanks.

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# Homework Help: DC Circuit trouble

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