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Understanding the Voltage Equation for a Separately Excited DC Motor
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[QUOTE="andrevdh, post: 5121186, member: 35979"] The coils of the armature is represented by a pure inductor and a resistor in the equivalent circuit. Going round the circuit we come to the conclusion that the supply voltage [I]V[SUB]t[/SUB] [/I]is [I]V[SUB]t[/SUB] = E[SUB]a[/SUB] + [FONT=Times New Roman]I[/FONT][SUB]a[/SUB] R[SUB]a[/SUB][/I] where [I]E[SUB]a[/SUB][/I] is the voltage over the pure inductor. Next they introduce a "new" variable, the voltage drop over the armature as a whole [I]V[SUB]a[/SUB] .[/I] Clearly this has to be equal to the supply voltage[I] V[SUB]t[/SUB] . [/I] [/QUOTE]
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Understanding the Voltage Equation for a Separately Excited DC Motor
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