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DC Offset

  1. Jun 22, 2007 #1
    If I have a string of 19 continuous bits 'high' followed by a bit 'low', how do I calculate the DC Offset if the pattern is repeated? Is it just [(19 - 1)*(the amplitude)]/(20)?

    Thanks for the help.
    Chris
     
  2. jcsd
  3. Jun 22, 2007 #2

    berkeman

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    Staff: Mentor

    Yes, that looks correct. You are just calculating the average value -- that would be the DC offset.
     
  4. Jun 23, 2007 #3

    NoTime

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    DC offset??
    Don't you mean equivilent DC voltage value?
    This would be the RMS value in a sine wave.

    AFAIK DC offset has to do with symmetry of the waveform around 0.
    It would be 50% of the high value if the low value is 0.
     
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