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**1. In the network given (Fig.1), the initial voltage on C1 is V1 and on C2 is V2 such that v1(0)=V1 and v2(0)=V2. At t=0 the switch K is closed.**

(b) Find v1(t) for t>0.

(c) Find v2(t) for t>0.

(d) From your results on (b) and (c), show that v1(∞)=v2(∞).

__(a) Find i(t) fo all time__.(b) Find v1(t) for t>0.

(c) Find v2(t) for t>0.

(d) From your results on (b) and (c), show that v1(∞)=v2(∞).

## Homework Equations

V=iR.

V=i/C∫i.dt

## The Attempt at a Solution

I'm lost on this one. I don't fully understand how to construct the equation for part (a). Is it:

i/C1∫i.dt

**-**i/C2∫i.dt+iR=0

Or

i/C1∫i.dt

**+**i/C2∫i.dt+iR=0

I'm having trouble understanding which one is the voltage drop and which one is the rise. Also, shouldn't the orientation of the capacitors also matter? For example, if we flip the capacitor C2 as shown in Fig. 2, how would the equations change?