- #1
Lancelot59
- 646
- 1
I'm asked to determine if for the solution
[tex]y=c_{1}e^{x}cos(x)+c_{2}e^{x}sin(x)[/tex]
for:
[tex]y"-2y'+2y=0[/tex]
whether a member of the family can be found that satisfies the boundary conditions:
[tex]y(0)=1[/tex], [tex]y'(\pi)=0[/tex]
Not quite sure what to do here. The examples in my book give boundary conditions for the same function, not derivatives.
When I put the first condition into y, I got c1=1, then substituting that result into the derivative condition I found c2=-1. So I found the constants, does this mean that there is a member of the family that can satisfy the boundary condition? For some reason I think there should be a Wronskian involved.
[tex]y=c_{1}e^{x}cos(x)+c_{2}e^{x}sin(x)[/tex]
for:
[tex]y"-2y'+2y=0[/tex]
whether a member of the family can be found that satisfies the boundary conditions:
[tex]y(0)=1[/tex], [tex]y'(\pi)=0[/tex]
Not quite sure what to do here. The examples in my book give boundary conditions for the same function, not derivatives.
When I put the first condition into y, I got c1=1, then substituting that result into the derivative condition I found c2=-1. So I found the constants, does this mean that there is a member of the family that can satisfy the boundary condition? For some reason I think there should be a Wronskian involved.