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Just a quick question (although there is a followup depending on the answer). In the formula ##E=\hbar \omega##, is E only kinetic energy or the total mechanical energy (kinetic energy plus potential energy). Thanks!
I know that, I'm asking about the E in the equation ##E=\hbar \omega##.BvU said:The Hamiltonian is kinetic + potential energy
Well, out with it !Isaac0427 said:although there is a followup depending on the answer
As I said, depending on the answer. If it was just the kinetic energy, I would have been confused about something, but apparently I was right to be confused because it is the total energy.BvU said:Well, out with it !
De Broglie's theory states that particles, such as electrons, have both kinetic and potential energy. The kinetic energy is the energy of motion, while the potential energy is the energy associated with the particle's position in an electric field.
2.De Broglie's theory was one of the key principles that led to the development of quantum mechanics. It helped to explain the wave-like behavior of particles, which was previously thought to only apply to waves.
3.The formula for calculating the kinetic energy of a particle according to De Broglie's theory is E = (h^2 * f^2)/(8 * m), where h is Planck's constant, f is the particle's frequency, and m is the particle's mass.
4.Yes, De Broglie's theory can be applied to all particles, including larger ones like atoms and molecules. However, it is most commonly used to describe the behavior of subatomic particles, such as electrons.
5.De Broglie's theory explains the dual nature of particles by showing that they exhibit both wave-like and particle-like behavior. This is known as wave-particle duality, and it is a fundamental concept in quantum mechanics.