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De Broglie wavelength of an electron

  1. Mar 29, 2009 #1
    1. The problem statement, all variables and given/known data
    What is the de Broglie wavelength of this electron?
    Given is 500 eV

    2. Relevant equations
    KE= 1/2 mv^2
    1 eV=1.602x19^-19 J

    3. The attempt at a solution
    I converted the 500 eV to 8.01x10^-17 via the given conversion. Now I'm stuck.
  2. jcsd
  3. Mar 29, 2009 #2
    The deBroglie wavelength is given by the relation

    [tex]\lambda = \frac{h}{p}[/tex]

    where [itex]h[/itex] is the plank constant and [itex]p[/itex] is momentum. I'm assuming the number in eV you were given is the kinetic energy of the electron--you can look up its mass to get it in terms of momentum through

    [tex] T \text{(kinetic energy)}=\frac{p^2}{2m}[/tex]

    Can you figure how to get the wavelength of it from this?
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