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De Broglie wavelength

  1. Dec 8, 2005 #1
    we were having a discussion about this in physics and my teacher mentioned a relationship between the formula and some angle (don't know which!) but it's not on the syllabus any more, i was wondering does anyone know anything about this?

    cheers for the help
     
  2. jcsd
  3. Dec 8, 2005 #2

    Chi Meson

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    Was there by any chance some mention of the "Compton effect"? Or was it mentioned in terms of x-rays? Or perhaps electron diffraction?

    The deBroglie wavelength is used in may advanced physics applications; you'd have to give us some kind of clue here.
     
  4. Dec 9, 2005 #3
    well it must be something pretty simple as it's only AS level physics, it came up during a discussion about the photoelectric effect...
     
  5. Dec 9, 2005 #4

    Chi Meson

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    My guess is that your teacher was talking about the Compton effect in which a photon collides with an electron. such a collision demonstrates the momentum of the photon since the electron recoils with a change in momentum. The photon (an x-ray) scatters at an angle theta according to the following formula:
    [tex]\lambda '- \lambda=(h/mc)(1-cos \theta)[/tex]

    the (h/mc) term is the "Compton wavelength" of the recoiling electron
     
    Last edited: Dec 9, 2005
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