How Does the De Broglie Wavelength Relate to Scattering Angles?

Broglie wavelength of the electronIn summary, during a discussion in physics class, the teacher mentioned a relationship between a formula and an angle that is no longer on the syllabus. The formula may be related to the Compton effect, which involves a collision between a photon and an electron and demonstrates the momentum of the photon. This effect is also related to the deBroglie wavelength of the electron.
  • #1
QueenFisher
we were having a discussion about this in physics and my teacher mentioned a relationship between the formula and some angle (don't know which!) but it's not on the syllabus any more, i was wondering does anyone know anything about this?

cheers for the help
 
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  • #2
Was there by any chance some mention of the "Compton effect"? Or was it mentioned in terms of x-rays? Or perhaps electron diffraction?

The deBroglie wavelength is used in may advanced physics applications; you'd have to give us some kind of clue here.
 
  • #3
well it must be something pretty simple as it's only AS level physics, it came up during a discussion about the photoelectric effect...
 
  • #4
My guess is that your teacher was talking about the Compton effect in which a photon collides with an electron. such a collision demonstrates the momentum of the photon since the electron recoils with a change in momentum. The photon (an x-ray) scatters at an angle theta according to the following formula:
[tex]\lambda '- \lambda=(h/mc)(1-cos \theta)[/tex]

the (h/mc) term is the "Compton wavelength" of the recoiling electron
 
Last edited:

1. What is the De Broglie wavelength?

The De Broglie wavelength is the wavelength associated with a moving particle, such as an electron or a photon. It is named after French physicist Louis de Broglie, who proposed that all particles have both wave-like and particle-like properties.

2. How is the De Broglie wavelength calculated?

The De Broglie wavelength can be calculated using the equation λ = h/mv, where λ is the wavelength, h is Planck's constant, m is the mass of the particle, and v is its velocity.

3. What is the significance of the De Broglie wavelength?

The De Broglie wavelength is significant because it demonstrates the wave-particle duality of matter. It suggests that particles, such as electrons, can exhibit both wave-like and particle-like behavior, and that their behavior is described by quantum mechanics.

4. How does the De Broglie wavelength relate to the Heisenberg uncertainty principle?

The De Broglie wavelength is related to the Heisenberg uncertainty principle through the concept of uncertainty in momentum and position. The uncertainty in the position of a particle is inversely proportional to the uncertainty in its momentum, and the De Broglie wavelength is used to calculate the momentum of a particle.

5. Can the De Broglie wavelength be observed in everyday objects?

No, the De Broglie wavelength is only significant for particles with extremely small masses, such as electrons and photons. The wavelengths of everyday objects, such as a baseball or a car, are too small to be observed or have any practical significance.

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