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I have a question regarding the use of de moivre formula:

I'm presented with a complex number [tex] z = (cos(v) + i sin(v))^n = 1[/tex]

I'm suppose to show that [tex]z^n = 1[/tex] is a root of unity. Is there a procedure on how to show this? If n = 6 and [tex]v = \frac{4 \pi}{6}[/tex]

Sincerely and Best Regards

Bob

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# De moivre formula Question

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