y'' -6y' + 9y = f(t)
The Attempt at a Solution
Turning it to heaviside functions I get:
y'' -6y' + 9y = u1 - u3
and I solve.
in the answers it should be:
y(t) = 2tet + u1(1/9 - 1/9e3(t-1)+ 1/3(t-1)e3(t-1)).
where did u3 go in the answers? why doesn't it appear? the u1 I can get just like that, but I can't seem to figure out where the u3 went and why there is a 2tet in there.