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Dead hex

  1. Dec 17, 2003 #1
    Question;

    If you and dead people can read hex, how many people can read hex?
     
  2. jcsd
  3. Dec 17, 2003 #2

    chroot

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    [itex]157255_8[/itex]

    - Warren
     
  4. Dec 17, 2003 #3
    Nope ;)
     
  5. Dec 17, 2003 #4

    chroot

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    Are you sure?

    - Warren
     
  6. Dec 17, 2003 #5
    yep... read again,
     
  7. Dec 17, 2003 #6
    ahh wait a min... :)
     
  8. Dec 17, 2003 #7
    you almost got it...read again....
     
  9. Dec 17, 2003 #8

    chroot

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    Heh, I'm dumb. Somehow I thought I pressed the 1 on my caculator, but I guess I didn't?

    [tex]157256_8[/tex]

    - Warren
     
  10. Dec 17, 2003 #9
    hehe well done,

    To be honest you are the quickest to get this I have seen, so i would say Dumb :)
     
  11. Dec 17, 2003 #10

    chroot

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    Heh, just the other day I used 0xDEADBEEF as a boundary identifier in a program... that one's classic, man.

    - Warren
     
  12. Dec 17, 2003 #11
    lol... hehe very funny
     
  13. Dec 17, 2003 #12

    enigma

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    Uh.

    I don't get it.
     
  14. Dec 17, 2003 #13

    NateTG

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    It's based on hexidecimal numbers
    0-F are digits so
    0xDEAD=13*4096+14*256+10*16+13 base 10
    so there are 0xDEAD+1 or 57006 people that can read hex.

    Of course, it would be tougher if you got some B!FF in there:

    If Biff and Dead people can read hex. How many people can read hex?

    Now we have 0x1FB1FF + 0xDEAD people.

    If I was feeling creative, I could probably concoct something even worse.
     
  15. Dec 17, 2003 #14

    chroot

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    But "I" is not a valid hexadecimal numeral... :wink:

    - Warren
     
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