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Decay chain solution

  1. Jun 17, 2013 #1
    For the decay chain N1 -> N2 -> N3 -> ... -> Ni -> ... -> Nd, how can I find the amount of particles of Ni, n(Ni), at any point in time t, with a single equation where i can vary from 1 to d? I have already seen WIkipedia's suggestion on the Bateman equations but that method seems to collapse for the case when i=d (as lambda=0 so we'd be dividing by 0).
     
  2. jcsd
  3. Jun 17, 2013 #2

    mfb

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    Staff: Mentor

    You can use the equation with an additional decay to Nd+1, and take the limit of an infinite lifetime of Nd. Alternatively, subtract all the other elements from the total number of particles.
     
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