 #1
 2
 0
Homework Equations
I was given all this information... I cannot figure it out whatsoever. I would post my attempts but there were too many. Any ideas would be helpful. I know the answer is 5.09 as the half life
Decay Constant of Copper 66
Sources do not emit radiation at a constant rate but fade away with time.
In this experiment, you monitor the count rate of a sample of copper 66 which has just been prepared.
The detector counts for one minute at each interval.
time(minutes) counts
0 932
1 813
2 710
3 619
4 540
5 453
6 435

time(minutes) counts
7 359
8 318
9 266
10 239
11 205
12 182
13 161
time(minutes) counts
14 138
15 121
16 108
17 92
18 80
19 70
20 61
The data in the table should satisfy the relation:
N=N0e(lambda)t
where, N0 = the number of counts at time 0
N = the number of counts after an elapsed time T
lambda = the decay constant for the specific isotope
t = the elapsed time
Plot the count rate vs the time on semilog paper using the data found in the table. Calculate the slope.
Hint#1: Make sure you calculate the slope in the right units and that the sign of the answer make sense.
Hint#2: From the formula above the value of the slope will be "lambda"
Be sure to enter the answer in the summary table in your lab outline.
The halflife, T, is defined as the time for the count rate to drop by a factor of 2.
(1/2)N0 = N0e^(lambda)T
T = 0.693/lambda
Homework Statement
i cannot find the half life/slope
Homework Equations
equations above
The Attempt at a Solution
my attempts were not posted because it would make this uber long