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Decay of rho meson to pions

  1. Nov 24, 2011 #1
    Hi all. I'm looking at the decay of a neutral ρ meson to two neutral π's. I think it is disallowed but I can't figure out why. The [itex]J^{P}[/itex] of the ρ is [itex]1^{-}[/itex] and [itex]0^{-}[/itex] for the neutral π's. The formula [itex]P(ρ^{0})=(-1)^{L}P(π^{0})P(π^{0})[/itex] then says that the decay is allowed provided the π's are produced in an L=1 state. If we insist that total angular momentum is conserved, we initially start with J=1 for the ρ which will decay to two π's with S=0 so using J=L+S, L=1 for the pions. If this argument is correct then the decay is not disallowed by parity. What else could disallow the decay? A colour argument? If it helps solve the problem [itex]ρ->π^{-}π^{+}[/itex] is allowed.
     
    Last edited: Nov 24, 2011
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  3. Nov 24, 2011 #2

    Vanadium 50

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    What else is conserved in strong interactions?
     
  4. Nov 24, 2011 #3

    Meir Achuz

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    Two identical pi0s cannot be in an antisymmetric L=1 state.
     
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