Hi all. I'm looking at the decay of a neutral ρ meson to two neutral π's. I think it is disallowed but I can't figure out why. The [itex]J^{P}[/itex] of the ρ is [itex]1^{-}[/itex] and [itex]0^{-}[/itex] for the neutral π's. The formula [itex]P(ρ^{0})=(-1)^{L}P(π^{0})P(π^{0})[/itex] then says that the decay is allowed provided the π's are produced in an L=1 state. If we insist that total angular momentum is conserved, we initially start with J=1 for the ρ which will decay to two π's with S=0 so using J=L+S, L=1 for the pions. If this argument is correct then the decay is not disallowed by parity. What else could disallow the decay? A colour argument? If it helps solve the problem [itex]ρ->π^{-}π^{+}[/itex] is allowed.(adsbygoogle = window.adsbygoogle || []).push({});

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# Decay of rho meson to pions

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