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Decaying muonic atom

  1. Jun 26, 2011 #1
    1. The problem statement, all variables and given/known data
    The electron in the Hydrogen atom can be replaced by the heavier muon resulting in a muonic atom. The muonic atom is not stable because the muon lives for 2.2 μs on average and then it decays into an electron and two neutrinos. However some very fast experiments can be performed on the muonic atom.
    --------------------------------------------------------------------------------
    What is the energy of the muon in the ground state?
    You will need the following masses for this problem:
    - electron : 0.5110 Mev/c2,
    - muon : 105.7 Mev/c2,
    - proton : 938.3 Mev/c2.



    2. Relevant equations

    [itex]\mu[/itex]=m_e/(1+(m_e/M));M=proton mass

    R_m=([itex]\mu[/itex]/M)[itex]R_{H}\ =\ 109.73731568549(83)\ \times\ 10^{5} m^{-1}[/itex

    E=-R_m(hc)/n2



    3. The attempt at a solution

    So I know to use these equations to find the energy, however, the place where I go wrong is that since the electron has been replaced with a muon I don't know if I need to replace the m_e with the muon mass
     
  2. jcsd
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