Decimal fraction to binary

  • Thread starter kadaj6
  • Start date
  • #1
31
0
ok so i have this code:

Code:
import java.util.Scanner;

class doubleEncodingClass {

	public static void main(String args[]) {

		byte largestPositiveByte   = 127;
		short largestPositiveShort = 32767;
		int largestPositiveInt     = 2147483647;
		long largestPositiveLong   = 9223372036854775807L;
		long largestPositiveLongPlusOne   = 9223372036854775807L;

		Scanner in = new Scanner(System.in);
		
		System.out.println("Next number (0 to stop): ");
		double l1 = in.nextDouble();
		double nextNumber = Math.ceil(l1);	
		double l2= (nextNumber - l1);
		
		
		while (nextNumber != 0) {
			
			int radix;
			
			int numBits = 8;  // FIX: Closest power of two greater or equal to minimal number of bits required by next number
			
			System.out.println("Bits Required: " +  numBits);
			
			radix = 10;
			System.out.println("Decimal: " + String.format("%s",  Long.toString( l,radix)).replace(' ','0'));

			radix = 2;
			System.out.println("Binary: " + String.format("%"+numBits+"s",  Long.toString( l,radix)).replace(' ','0'));

			radix = 8;
			System.out.println("Octal: " + String.format("%"+((int) Math.ceil(numBits/3.0))+"s",  Long.toString( l,radix)).replace(' ','0'));

			radix = 16;
			System.out.println("Hexadecimal: 0x" + String.format("%"+numBits/4+"s",  Long.toString( l,radix)).replace(' ','0'));
			
			System.out.println("");
			System.out.println("Next number: (0 to stop)");
			nextNumber = in.nextDouble();
		}
		System.out.println("Good Bye");
	}
}

im trying to grab the decimal part of "l2" and represent it in binary,
this codes needs to tell me the binary of whole numbers and the decimal part of numbers...

plz help me
 

Answers and Replies

  • #2
jim mcnamara
Mentor
4,292
2,903
Try an abstract datatype - use a class as "structs" with members having a public access specifier and no methods .
 

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