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 Homework Statement:
 A 30kg object is being pulled across a horizontal surface. The acceleration is 1.2 m/s2. The object is being pulled by a handle that is at 25 degrees. Friction force is 10 N. What forces can we find?
 Relevant Equations:

Fg = m * g
Fnet = m * a
Fa = Fax / cos(angle)
Fax = Fax leftward  Fax rightward
Fay = Fa * sin(angle)
Fg = m * g:
Fg = 30 * 9.8 = 294 N
Fnet = m * a:
Fnet = 30 * 1.2 = 36 N
Fax = Fnet + Ff:
Fax = 36 + 10 = 46
Fa = Fax / cos(angle):
Fa = 46 / cos(25) = 50.75
Fay = Fa * sin(angle):
Fay = 50.76 * sin(25) = 21.45
Fn = Fg  Fay:
Fn = 294  21.45 = 272.55
Ff = mu kinetic * Fn, solving for coefficient:
Coefficient of friction = 10 / 272.55 = .035
Does this look correct?
Fg = 30 * 9.8 = 294 N
Fnet = m * a:
Fnet = 30 * 1.2 = 36 N
Fax = Fnet + Ff:
Fax = 36 + 10 = 46
Fa = Fax / cos(angle):
Fa = 46 / cos(25) = 50.75
Fay = Fa * sin(angle):
Fay = 50.76 * sin(25) = 21.45
Fn = Fg  Fay:
Fn = 294  21.45 = 272.55
Ff = mu kinetic * Fn, solving for coefficient:
Coefficient of friction = 10 / 272.55 = .035
Does this look correct?