Deducing as much as possible from m, a, Ff, and angle (pulling an object horizontally with a handle)

  • #1
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Homework Statement:
A 30kg object is being pulled across a horizontal surface. The acceleration is 1.2 m/s2. The object is being pulled by a handle that is at 25 degrees. Friction force is 10 N. What forces can we find?
Relevant Equations:
Fg = m * g
Fnet = m * a
Fa = Fax / cos(angle)
Fax = Fax leftward - Fax rightward
Fay = Fa * sin(angle)
Fg = m * g:
Fg = 30 * 9.8 = 294 N

Fnet = m * a:
Fnet = 30 * 1.2 = 36 N

Fax = Fnet + Ff:
Fax = 36 + 10 = 46

Fa = Fax / cos(angle):
Fa = 46 / cos(25) = 50.75

Fay = Fa * sin(angle):
Fay = 50.76 * sin(25) = 21.45

Fn = Fg - Fay:
Fn = 294 - 21.45 = 272.55

Ff = mu kinetic * Fn, solving for coefficient:
Coefficient of friction = 10 / 272.55 = .035


Does this look correct?
 

Answers and Replies

  • #2
haruspex
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Making assumptions about how you are defining your variables, it all looks ok, except "Fax = Fax leftward - Fax rightward". What did you mean by that?
Your answers show too many significant figures, given the precision of the provided numbers. Round to at most three.
 

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