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Deduce that
n
Sigma (2r)^3 = 2n^2 (n+1)^2
r=1
I'm not exactly sure how to start.
n
Sigma (2r)^3 = 2n^2 (n+1)^2
r=1
I'm not exactly sure how to start.
Deduce that
n
Sigma (2r)^3 = 2n^2 (n+1)^2
r=1
I'm not exactly sure how to start.
The result of my previous thread was 1.
Oh right sorry, I got locked out of my previous account. The part with the k + 1 case?
1
sigma r^3 = 1^2(1+1)^2/4?
r=1
Deduce that
n
Sigma (2r)^3 = 2n^2 (n+1)^2
r=1