- #1
msimard8
- 57
- 0
Here is the question. I have to prove it.
Prove that the square of an odd integer is always of the form 8k+1, which k is an integer.
Now I do not know how to start it. But this is what I came up with.
odd integer= 2k+1
therefore the square of an odd integer (2k+1)^2
i have used inductive reasoning to prove that is statement is correct
example
if k=1 then the expression becomes 9 (3^2)
if k =3 then the epression becomes 25 (5^2)
if k=6 then the expression becomes 49 (7^2)
now how to prove it with deductive reasonings.
I am not sure how to start this one.
Can you please give me a hint
Prove that the square of an odd integer is always of the form 8k+1, which k is an integer.
Now I do not know how to start it. But this is what I came up with.
odd integer= 2k+1
therefore the square of an odd integer (2k+1)^2
i have used inductive reasoning to prove that is statement is correct
example
if k=1 then the expression becomes 9 (3^2)
if k =3 then the epression becomes 25 (5^2)
if k=6 then the expression becomes 49 (7^2)
now how to prove it with deductive reasonings.
I am not sure how to start this one.
Can you please give me a hint