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Definite inegral

  1. Nov 28, 2009 #1
    Use the definiton of the definite inegral (with right hand rule) to evaluate the following integral. Show work please

    Can NOT use shortcut method.. but be the long process


    1
    S (3x^2 - 5x - 6) dx
    -4

    edit:
    i got this so far
    1
    S (3x^2 - 5x - 6) dx = [3x^3 /3 - 5x^2/2 - 6x], (1, -4)
    -4
    = 3*1/ 3 - 5*1 /2 - 6*1 - (3*4^3 - 5*4^2 - 6*2)

    but iam lost in the simplification


    edit: NVm i have no idea how to do the long method.. any 1 help <3 lpz
     
    Last edited: Nov 28, 2009
  2. jcsd
  3. Nov 28, 2009 #2
    That looks like the 'shortcut' method, but it's not a bad idea to do that real quick to check yourself.

    What you want to do (as per the directions) is evaluate it using Riemann sums. Specifically, right-hand Riemann sums.
     
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