# Definite inegral

1. Nov 28, 2009

### DemiMike

Use the definiton of the definite inegral (with right hand rule) to evaluate the following integral. Show work please

Can NOT use shortcut method.. but be the long process

1
S (3x^2 - 5x - 6) dx
-4

edit:
i got this so far
1
S (3x^2 - 5x - 6) dx = [3x^3 /3 - 5x^2/2 - 6x], (1, -4)
-4
= 3*1/ 3 - 5*1 /2 - 6*1 - (3*4^3 - 5*4^2 - 6*2)

but iam lost in the simplification

edit: NVm i have no idea how to do the long method.. any 1 help <3 lpz

Last edited: Nov 28, 2009
2. Nov 28, 2009

### xeno_gear

That looks like the 'shortcut' method, but it's not a bad idea to do that real quick to check yourself.

What you want to do (as per the directions) is evaluate it using Riemann sums. Specifically, right-hand Riemann sums.