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Homework Help: Definite Integral (BIG BOSS)

  1. Oct 31, 2004 #1
    Who can solve or give hint for the following integral?

    [tex]\int_0^4 3x \sqrt{5^2-x^2}dx [/tex] :tongue: :eek:
     
  2. jcsd
  3. Oct 31, 2004 #2

    Hurkyl

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    Try a technique you learned in class!
     
  4. Oct 31, 2004 #3
    Try [tex]u=5^2-x^2[/tex], which means [tex]du = -2xdx[/tex]
     
  5. Oct 31, 2004 #4
    Thanks!

    [tex]u^2=5^2-x^2[/tex] << This one works better. :tongue:
     
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