# Definite Integral Homework

Consider the Integral: a=0 b=1 (x^2)(sqrt(9x+8))dx

Does u=(9x+8) ?
can we factor out the x^2?

We have to give the value that the definite integral is

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you have to use integration by parts. you want

u= 9x+8
du=9dx
v= (x^3)/3
dv=x^2dx

then figure out [ uv - integral of (vdu) ]
(x^3)/3 * (9x+8) - integral of [ (x^3)/3 * 9dx)]