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Homework Help: Definite integral

  1. Dec 7, 2005 #1
    What is the integral of 110*1.10^(t) from b=35 to a=0 (b being hte upper number to the integral sign and a being the lower number to the integral sign)

    From the textbook it says it's the constant c=110 times the sum of the integral of b - the integral of a.

    so how do i get integral of a and b?

    Thank you for replying!!!
  2. jcsd
  3. Dec 7, 2005 #2
    You could try to make use of [tex]\exp \left( {t\log \left( {1.10} \right)} \right) = \exp \left( {\log \left( {1.10} \right)^t } \right) = 1.10^t [/tex].
  4. Dec 7, 2005 #3
    Thanx Benny~!!! Thank You!!!!
  5. Dec 7, 2005 #4
    I got another problem if you could help again... I would really really appreciate it

    now to so far i know its antiderivative starts with

    10t+ ... something... could you guys give me some hint as to how to continue?
  6. Dec 7, 2005 #5
    If k is a constant then [tex]\int {e^{kt} } dt = \frac{1}{k}e^{kt} + c[/tex] where c is an arbitrary constant. Just use that to integrate the exponential. By the way, I would have thought that this one would have been very simple for you if you were able to do the first problem you asked about.
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