I don't know how to solve this really easy integral.(adsbygoogle = window.adsbygoogle || []).push({});

suppose: [tex] a=2 m/s^2 [/tex]

[tex] a = dv / dt [/tex]

[tex] \int^b_a a \ dt = \int^b_a dv [/tex]

[tex] \int^b_a 2 \ dt = v_{b} - v_{a} [/tex]

[tex] 2t_{b} - 2t_{a} = v_{b} - v_{a} [/tex]

[tex] v_{b} = v_{a} + 2t_{b} - 2t_{a} [/tex]

I hope everything is ok up to this point. Then I want to know the position: r, and I need to use the same b and a that I have already use before, but...

[tex] v = dr / dt [/tex]

[tex] \int^b_a v \ dt = \int^b_a dr [/tex]

[tex] \int^b_a ( v_{a} + 2t_{b} - 2t_{a} ) \ dt = r_{b} - r_{a} [/tex]

[tex] v_{a}t_{b} - v_{a}t_{b} ...... \ ??? = r_{b} - r_{a} [/tex]

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# Homework Help: Definite integrals

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