∫dt/(t^2 +2tcos a + 1)
(Limits of the integral are from 0 to 1)
The Attempt at a Solution
Put t=sin a
∫dt/(t^2 +2tcos a + 1) = ∫cos a da/(sin^2 a + sin 2a + 1) [ limits of integration changed to 0 to π/2]
= ((cosec a)/2) ∫sin 2a da/(sin^2 a + sin 2a + 1)
I couldn't figure out what to do next... Please help!!
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