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Deflection of a jet of water

  1. Aug 16, 2008 #1
    1. The problem statement, all variables and given/known data
    A jet of water going through a nozzle is deflected by a flat plate. Get Q, Velocity, Force

    The volumetric flow rate of water through the nozzle is 10 Litres in 7 seconds

    The water temperature is 20 degrees celcius.
    We are using a flat plate so theta = 90 degrees
    Velocity coefficient C = 1

    2. Relevant equations
    Q (volume flow rate) = volume / time
    Velocity = Q / area of nozzle
    Force = density of water * Area of nozzle * velocity^2 * (1 - C*cos theta)

    3. The attempt at a solution
    Density of water at 20 degrees = 998.2 kg/m^3
    Q = 0.01 / 7
    Q = 1.429 (10^3) m^3/s

    I dont know how to get area of nozzle

    Using C = 1, theta = 90:
    F = 1000 * area of nozzle * V^2
  2. jcsd
  3. Aug 17, 2008 #2


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    Homework Helper

    Hi michael7777! :smile:

    I agree with you … there isn't enough information. :confused:

    (btw, another way of calculating it is force = rate of change of momentum = mass x velocity/time … but again, we don't know the velocity. :cry:)
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