- #1

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I have:

[tex]y_s = kW[/tex]

T1 = 0

V1 = mgh

T2 = 0 when deflection is at a max

[tex]V2 = -mgy_m[/tex]

I'm pretty sure that V2 should also include the potential energy stored in the beam, but I don't know how to express that. Would it be similar to a spring? V(beam) = 1/2ky^2 ? That's my guess, but there must be a logical way of proving it.

I think I can do the rest once I find the expression for the potential energy inside the elastic beam.