(adsbygoogle = window.adsbygoogle || []).push({}); [SOLVED] Deflection of Plates

Answer choices: A) 63V B) 112V C) 520V D) 642V E) 882V

y = .5cm = 5 x 10^-3 m

x = 3cm = 3 x 10 ^-2 m

angle = 10 degrees

acceleration(a) = ((1.602 x 10^-19) (15000))/(9.11 x 10^-31) = 2.6 x 10^15 m/s^2

Force(F) = 2.6 x 10 ^15(9.11 x 10^-31) = 2.4 x 10^15 N

E = F/e = (2.4 x 10 ^-15)/(1.602 x 10^-19) = 1.5 x 10^4 N/C

velocity(v) = sqrt(2 x (2.6 x 10^15) x (.005)) = 5.1 x 10^6 m/s

y = (1/2) x ((1.602 x 10^-19)/(9.11 x 10^-31)) x ((1.5 x 10^4)/(5.1 x 10^6)^2) x (.03) = 1.5 m

displacement = y tan 10 = (1.5) x (tan 10) = .26

Voltage(V) = ?

I am lost here on how to calculate the voltage applied tp to plates.

V = E x .005 = 75....But the answer is not one of the choices

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# Homework Help: Deflection of Plates

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