1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Degenerate Fermi temperature of 2 fermionic gases

  1. Apr 27, 2009 #1
    1. The problem statement, all variables and given/known data

    Consider 2 fermionic gases, each made of 10^6 atoms occupying 10^-3 m^3 volume: tritium, the nucleus containing one proton and two neutrons, and potassium, 19 protons and 21 neutrons. Which gas do you have to cool more in order for a Fermi surface to form? Find the ratio of the temperatures where the 2 gases become degenerate.

    2. Relevant equations

    Fermi Enegery = (h^2/8m)(3N/PiV)^(3/2)
    Fermi Temperature = Fermi Energy / k = (h^2/8km)(3N/PiV)^(3/2)

    3. The attempt at a solution

    Hmmm...I think I am trying to solve for the Fermi temperature here...
    since both N and V are the same for both gases...if I just take the ratio of the Fermi temperature of the 2 gases I will only have the ratio of their masses left...

    Since Potassium is heavier than tritium, does it mean potassium will have to be cooled more to become degenerate?

    Is the ratio of their degenerate temperature simply the ratio of their masses?

    Thank you for the help! :smile:
     
  2. jcsd
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted



Similar Discussions: Degenerate Fermi temperature of 2 fermionic gases
  1. 2 blocks, 2 pulleys (Replies: 0)

Loading...