- 1
- 0
Consider f: S^{1} -> S^{1}: (cos 2 pi x, sin 2 pi x) -> (cos 2 k pi x, sin 2 k pi x).
How to show directly from the homological definition (without using Hurewicz etc) that degree(f) = k?
How to show directly from the homological definition (without using Hurewicz etc) that degree(f) = k?