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Degree of a Map

  1. Oct 20, 2008 #1
    Hi,

    I am having some problems understanding the degree of a continuous map g:circle --> circle

    I have found a definition in Munkres (pg 367) that I can't really understand (I'm an engineering student with little algebraic topology) and one in Lawson (pg 181), Topology:A Geometric approach, that makes some sense.

    Lawson defines it:

    For g as above, consider p : I --> circle and a lift h:I --> R
    such that gp=ph

    Then define the degree of g as

    deg g =h(1)-h(2)

    Intuitively I understand this to be the integer number of times the image of the circle wraps around the circle under g? If so, what about the continuous function g(x)=exp(i*pi*x/2) where x is in[0,2pi). The image would only wrap around half the circle, which would be homotopic to the constant map, a map of degree 0...but according to the above definition this would have degree 1/2?

    Thanks for any help!

    Regards,
    Mike
     
    Last edited: Oct 20, 2008
  2. jcsd
  3. Oct 21, 2008 #2
    Your example doesn't work because [0, 2pi) is not a circle. If you try to make a circle out of it by identifying 0 and 2pi, then your map would be discontinuous, since g(0) = 1 and g(2pi) = -1.

    (Sorry that this isn't a very formal argument, but I think it gets the point across.)
     
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