- #1
Kummer
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Let [tex]p_1,p_2,...,p_n[/tex] be distinct primes.
Show that [tex][\mathbb{Q}(\sqrt{p_1},\sqrt{p_2},...,\sqrt{p_n} ) : \mathbb{Q}]= 2^n[/tex]
Show that [tex][\mathbb{Q}(\sqrt{p_1},\sqrt{p_2},...,\sqrt{p_n} ) : \mathbb{Q}]= 2^n[/tex]
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