Molar Specific Heat of a Gas in Terms of R & s

In summary: This means that for each degree of freedom, the average energy of the molecule is ##\frac 12 k_{\rm B}T##.In summary, the equipartition theorem states that each degree of freedom of a gas molecule has an associated energy of 1/2k_B*T. Using this theorem, we can determine the molar specific heat, C_v, by using the formula C_v= (1/n)(dU/dT). Additionally, we can use the molar specific heat to determine the number of energetically accessible degrees of freedom of a gas molecule. For example, at room temperature, cis-2-butene has a molar specific heat of 70.6 J/mol*K, which corresponds
  • #1
doggieslover
34
0
Part A
Using the equipartition theorem, determine the molar specific heat, C_v, of a gas in which each molecule has s degrees of freedom.
Express your answer in terms of R and s.

Okay, I know that the equipartition theorem is 1/2k_B*T

and molar specific heat is C_v= (1/n)(dU/dT)

But I don't know where to go from here, please help?

Part B

Given the molar specific heat C_v of a gas at constant volume, you can determine the number of degrees of freedom s that are energetically accessible.

For example, at room temperature cis-2-butene, \rm C_4 H_8, has molar specific heat C_v=70.6\;{\rm \frac{J}{mol \cdot K}}. How many degrees of freedom of cis-2-butene are energetically accessible?
Express your answer numerically to the nearest integer.
 
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  • #2
doggieslover said:
But I don't know where to go from here, please help?
A monatomic molecule has three (translational) degrees of freedom and molar specific heat ##C_V=\frac{3}{2}k_BT.## Does this help?
 
  • #3
doggieslover said:
Okay, I know that the equipartition theorem is 1/2k_B*T
Your confusion arises because ##\frac 12 k_{\rm B}T## isn't the equipartition theorem. Theorems are generally statements whereas ##\frac 12 k_{\rm B}T## by itself is akin to a single word.

The principle of equipartition of energy states that each degree of freedom has, on average, an associated energy per molecule of ##\frac 12 k_{\rm B}T##.
 

What is the molar specific heat of a gas?

The molar specific heat of a gas is the amount of heat required to raise the temperature of one mole of the gas by one degree Celsius. It is commonly denoted by the symbol Cm.

How is the molar specific heat of a gas measured?

The molar specific heat of a gas can be measured experimentally using a calorimeter. The gas is placed in a container and heated to a known temperature. The heat energy required to raise the temperature of the gas is then measured, and the molar specific heat can be calculated using the formula Cm = q / (nΔT), where q is the heat energy, n is the number of moles of gas, and ΔT is the change in temperature.

What is the relationship between molar specific heat and the gas constant (R)?

The molar specific heat of a gas is directly proportional to the gas constant, R. As R increases, so does the molar specific heat. This relationship is expressed by the equation Cm = R/(s-1), where s is the number of degrees of freedom of the gas molecules.

How does the number of degrees of freedom affect the molar specific heat of a gas?

The number of degrees of freedom, denoted by s, represents the number of ways in which the gas molecules can store and transfer energy. The molar specific heat of a gas increases as the number of degrees of freedom increases, since more energy is required to raise the temperature of the gas.

What is the significance of the molar specific heat in thermodynamics?

The molar specific heat of a gas is an important quantity in thermodynamics, as it helps determine the amount of heat energy required to change the temperature of a gas. It is also used in calculations involving the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system.

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