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Degrees of Freedom

  1. Feb 18, 2010 #1
    In the Chi-square test, my textbook says that degrees of freedom are the number of independent variables minus one so df = n - 1

    does this mean that that n is equal to the number of observed values from the equation aka the number of times I've added together the numbers?

    sum [(O-E)^2]/E

    Is there an instance where it isn't equal to the number of observed values I have?

    (there's an example in my book (but no answer) with an experiment with observed values of 2 trials of genetic crosses where observed in
    trial 1 was 0.5
    trial 2 was 0.3
    but both of these values were measuring the same variable which was heterozygosity. The expected value is 0.8. Does this mean the df = 1? or is it 0 since there is only 1 independent variable?)

    thanks!
     
  2. jcsd
  3. Feb 23, 2010 #2
    df=n-1, n means number of the random variables, in this case n is the number of trials. df=n-1=2-1=1
     
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