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f(x) = 3-2x, x0=3, E=.02

Here is my attempt:

Lim (3-2x) as x->3 = -3

-.02 < |3-2x - 3| <.02

-.02 < |-2x| < .02

.01 > x > -.01

-2.99 > x-3 > -3.01

-2.99 > |x-3|

Delta= -2.99

Is this right? I'm really confused, any help would be greatly appreciated, even just an explanation. Thanks.