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Delta - Epsilon bound

  1. Jun 28, 2012 #1
    Use the delta-epsilon definition to prove f(x,y) = y/(1+x2) is continuous at (0,0)


    Attempts:


    So I'm doing some work and my main issue is finding a bound for the denominator of 1+x2:

    So work wise I have something looking like:

    [itex]\delta[/itex]/(|1| + |x2| ). How could I found a good bound?
     
  2. jcsd
  3. Jun 28, 2012 #2

    SammyS

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    An lower bound for 1+x2 is definitely 1.

    That makes and upper bound of 1 for 1/(1+x2) .
     
  4. Jun 28, 2012 #3
    thanks
     
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