# Delta - Epsilon bound

1. Jun 28, 2012

### trap101

Use the delta-epsilon definition to prove f(x,y) = y/(1+x2) is continuous at (0,0)

Attempts:

So I'm doing some work and my main issue is finding a bound for the denominator of 1+x2:

So work wise I have something looking like:

$\delta$/(|1| + |x2| ). How could I found a good bound?

2. Jun 28, 2012

### SammyS

Staff Emeritus
An lower bound for 1+x2 is definitely 1.

That makes and upper bound of 1 for 1/(1+x2) .

3. Jun 28, 2012

thanks