let [tex]f(y)=\int_0^2 \delta(y-x(2-x))dx[/tex]. Find f(y) and plot it from -2 to 2. I know how to calculate [tex]\delta (g(x))[/tex] but i am not sure how to treat it with the y. I thought possibly to solve the quadratic in the delta function to find what x will equal for the roots in terms of y and got 1+(1-y)^1/2 and 1-(1-y)^1/2. i am not sure though how to find f(y) with the integral. any suggestions?