Delta Squared?

1. Jan 26, 2010

Zerius

How does one deal with a delta squared ? For example, volume is a function of del Diameter and del Length.

If i let v = d^2(pi)L/4, and then call the d and L del. d and del L, when i separate for d i get del d^2

So i'm wondering if there are any special rules for squaring a "del"

2. Jan 26, 2010

tiny-tim

Hi Zerius!

(have a del: ∆ and try using the X2 tag just above the Reply box )
You mean as in π(∆d)2(∆L)/4 ?

(∆d)2 is just the square of ∆d.

What is the context? Is this part of some larger problem?

3. Jan 26, 2010

HallsofIvy

All you have done here is call ordinary numbers "delta d" and "delta L". There is nothing at all different about that.

If you are talking about differentials, then with $V= \pi r^2 L$, $dV= 2\pi r L dr+ \pi r^2 dL$. There is only one "dr".

By the way "del" is a common way of refering to the $\nabla$ operator so it is not a good idea to shorten "delta" to "del".