- #1

- 71

- 0

the time of flight of the cannonball for this maximum range R is given by

1.t=(1/3^1/2)vo/g

2.t=3^1/2(vo/g)

3.t=2^1/2(vo/g)

4.t=2(vo/g)

5.t=1/2(vo/g)

6.1/(2^1/2)(vo/g)

7.t=4(vo/g)

8.t=(1/4)(vo/g)

9.t=(2/3)(vo/g)

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter nrc_8706
- Start date

- #1

- 71

- 0

the time of flight of the cannonball for this maximum range R is given by

1.t=(1/3^1/2)vo/g

2.t=3^1/2(vo/g)

3.t=2^1/2(vo/g)

4.t=2(vo/g)

5.t=1/2(vo/g)

6.1/(2^1/2)(vo/g)

7.t=4(vo/g)

8.t=(1/4)(vo/g)

9.t=(2/3)(vo/g)

- #2

VietDao29

Homework Helper

- 1,424

- 3

Because you just need to find the time of flight, you don't need the x-component of your initial velocity, you just need the y-component of the initial velocity. So first, you can try to find out the y-component of the velocity.

Then, note that the object has the acceleration of g (downard). Can you find out the time in flight of the object?

Viet Dao,

- #3

- 71

- 0

thank you viet dao, i figured it out.

- #4

- 71

- 0

but now how do you find max height?

do u use y=voyt + 1/2gt^2?

- #5

VietDao29

Homework Helper

- 1,424

- 3

Because the object has the acceleration of g (downward), so the y-component of the initial velocity decreases, and the object moves upwards slowlier and slowlier, finally when the y-component of the velocity is

You can use:

v

Here a = -g (if you choose the positive direction upward).

v

v

Here, you just need the y-component, so the v

v

You can use that and solve for d, which's the object's max height.

Viet Dao,

Share:

- Replies
- 8

- Views
- 924