- #1
redrzewski
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There's a problem from Rudin's Functional Analysis where I need to show something is a dense subspace of 1st category.
But I thought that it was the definition of dense that its closure is the whole space. Hence the closure doesn't have empty interior. So the dense subspace can't be 1st category.
Can someone clarify?
thanks
But I thought that it was the definition of dense that its closure is the whole space. Hence the closure doesn't have empty interior. So the dense subspace can't be 1st category.
Can someone clarify?
thanks