(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

a) If the part of an iceberg above sea level is one ninth of the whole, what is the density of ice?

b)How much of the iceberg would show if it moved into a fresh water region?

2. Relevant equations

Density of sea water=1025kgm^-3

Density of fresh water 1000kgm^-3

Weight displaced=upthrust

Force due to gravity = mg

3. The attempt at a solution

For part a) I equated the upthrust and the force due to gravity, by applying Newtons first law. However I am confused as to whether I should also take into account the atmospheric pressure pressing the part of the iceberg above sea level down. In all the stuff I've read no one seems to take it into account when finding the density of an iceberg. Is there a reason for this?

In part b) I think you again apply Newtons first law and use the ice density calculated in part a),

[tex]\rho_{ice}*g*v_{ice}=\rho_{water}*g*v_{water}[/tex]

[tex]\frac{\rho_{ice}}{\rho_{water}}=\frac{v_{water}}{v_{ice}}[/tex]

Which gives the proportion of ice under the water.

Please could someone help me?

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# Homework Help: Density of an iceberg

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