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Density of Gold

  1. Aug 17, 2014 #1
    1. Problem: Gold, which has a density of 19.32 g/cm3, is the most ductile metal and can be pressed into a thin leaf or drawn out into a long fiber. (a) If a sample of gold with a mass of 2.274 g, is pressed into a leaf of 8.678 μm thickness, what is the area (in m2) of the leaf? (b) If, instead, the gold is drawn out into a cylindrical fiber of radius 2.200 μm, what is the length (in m) of the fiber?


    2. Relevant equations: a=pi x r^2 and (a)(l)= part a



    3. The attempt at a solution: part a= 0.01356, and I tried plugging it into the equation (1.521x10^-11 m^2)(l)=0.01356

    If anyone could find the error in part B!! Please Help
     
  2. jcsd
  3. Aug 17, 2014 #2

    SteamKing

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    Units? Showing your work?
     
  4. Aug 17, 2014 #3

    AlephZero

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    The "(a)(l)= part a" looks wrong. The answer to part a is an area. You cant say "area times length = area".

    That looks right (except you forgot the units).

    I don't understand what you did for part (b).
     
  5. Aug 17, 2014 #4

    NascentOxygen

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    Don't forget that the leaf has two sides, so there are two surface areas. This could be a trick question! :smile:

    So state your answer as ... m2 per side for each of 2 sides.

    If you knew the shape, you could also work out the area of its other very narrow side/s. :wink:
     
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