Questions about the Density Operator Formulation of Quantum Mechanics

In summary, the density operator, also known as the density matrix, is a mathematical representation of the state of a quantum mechanical system. It describes the probabilities of all the possible states that the system can be in, as well as the correlations between these states. It is different from a wave function in that it describes the state of the entire system, rather than just a single particle. The density operator is used to calculate statistical properties of a quantum system and describe its evolution over time. It can be used for both pure and mixed states, and relates to the uncertainty principle by taking into account the inherent uncertainty in a quantum system's properties.
  • #1
CPL.Luke
441
1
so I've been reading about the density operator formulation of quantum mechanics and I have some questions

what is the density operator analog of the schrodinger equation that determines the time evolution?

and how do you perform a projection measurement on a quantum system in the density operator formulation?

how would you use it to describe a system like the infinite square well?
 
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  • #2
CPL.Luke said:
what is the density operator analog of the schrodinger equation that determines the time evolution?

[itex]i\hbar\dot\rho=[H,\rho][/itex], where [itex]\rho[/itex] is the density operator.
CPL.Luke said:
how do you perform a projection measurement on a quantum system in the density operator formulation?

Replace [itex]\rho[/itex] with [itex]P\rho P[/itex]. where [itex]P[/itex] is the projection operator.
CPL.Luke said:
how would you use it to describe a system like the infinite square well?

You use the above formulae for time evolution and measurement.
 
  • #3
is it possible to solve for the density operator and possible outcomes of a measurement without having to use the standard wave mechanics?

sorry I'm not very used to seeing an equation which appears to only contain operators.

also do you mean the partial derivative with respect to time when you write p dot?
 
  • #4
CPL.Luke said:
is it possible to solve for the density operator and possible outcomes of a measurement without having to use the standard wave mechanics?

Yes. In some cases, density operators allow for simpler calculations. Example, find the state corresponding to spin-1/2 in the direction of the unit vector [tex]\vec{u} = (u_x,u_y,u_z)[/tex].

The operator for spin in that direction is [tex]\sigma_u = \vec{\sigma}\cdot u[/tex] where [tex]\vec{\sigma}[/tex] is the 3-vector of the Pauli spin matrices. This squares to 1 so an eigenstate for spin in the u direction is [tex]1+\sigma_u[/tex]. These are normalized so they are idempotent so the normalized state is [tex](1+\sigma_u)/2[/tex], which you can verify is idempotent.

Then to convert this into a state vector (wave function) solution to the eigenvector problem for spin in the u direction, simply taken any nonzero column vector in the matrix. Since there are two columns in the matrix, there are two choices. Ignoring the division by 2, and not bothering to normalize the vector, the two choices are:
[tex]\left(\begin{array}{c}1+u_z\\u_x+iu_y\end{array}\right),
\left(\begin{array}{c}u_x-iu_y\\1-u_z\end{array}\right)[/tex]
For the Dirac case general solution, see:
http://en.wikipedia.org/wiki/Dirac_spinor
where they currently call the 4x4 matrix the "projection operator", another, more general, name for the density matrix quantum state.

By the way, the wave function analogy to "taking any nonzero column" is to choose any point where the density operator function is nonzero in the second entry. That is, if [tex]\rho(x,x')[/tex] is a density matrix solution to Schroedinger's equation, and b is a point where [tex]\rho(x,b)[/tex] is not identically zero over x, then [tex]\psi(x) = \rho(x,b)[/tex] is a solution to Schroedinger's equation.


CPL.Luke said:
also do you mean the partial derivative with respect to time when you write p dot?

Yes. Of course it's actually rho. To write LaTeX for this, enter the following, without the spaces: [ t e x ] \ d o t { \ r h o } [ / t e x].
 

1. What is the density operator in quantum mechanics?

The density operator, also known as the density matrix, is a mathematical representation of the state of a quantum mechanical system. It describes the probabilities of all the possible states that the system can be in, as well as the correlations between these states.

2. How is the density operator different from a wave function?

The wave function describes the state of a single particle in a quantum system, while the density operator describes the state of the entire system. The wave function is a complex-valued function, while the density operator is a matrix that can be used to calculate the probabilities of different outcomes in a measurement.

3. How is the density operator used in quantum mechanics?

The density operator is used to calculate statistical properties of a quantum system, such as the average value of an observable or the probability of a particular measurement outcome. It is also used to describe the evolution of a quantum system over time and to study the entanglement of multiple particles.

4. Can the density operator be used for both pure and mixed states?

Yes, the density operator can be used for both pure and mixed states. In a pure state, the density operator is a projection operator onto the wave function of the system. In a mixed state, the density operator is a weighted sum of projection operators onto different wave functions.

5. How does the density operator relate to the uncertainty principle?

The uncertainty principle states that certain pairs of physical properties, such as position and momentum, cannot be simultaneously known to arbitrary precision. The density operator takes into account this uncertainty by representing a mixed state as a sum of pure states, each with their own probabilities. This allows for a more complete description of a quantum system, taking into account the inherent uncertainty in its properties.

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