# Density wave equation

1. Sep 14, 2012

### Dustinsfl

Traffic is moving with a uniform density of $\rho_0$.
$$\frac{\partial\rho}{\partial t} + c(\rho)\frac{\partial\rho}{\partial x} = \beta_0$$
where
$$c(\rho) = u_{\text{max}}\left(1 - \frac{2\rho}{\rho_{\text{max}}}\right).$$
Show that the variation of the initial density distribution is given by
$$\rho = \beta_0t + \rho(x_0,0)$$
along a characteristic emanating from $x = x_0$ described by
$$x = x_0 + u_{\text{max}}\left(1 - \frac{2\rho(x_0,0)}{\rho_{\text{max}}}\right)t - \beta_0\frac{u_{\text{max}}}{\rho_{\text{max}}}t.$$

So we have $\frac{dt}{ds} = 1$, $\frac{dx}{ds}=c(\rho)$ and $\frac{d\rho}{ds} = \beta_0$.
Then $t(s) = s + c$ where $t=s$ when $t(0) = 0$.
Not sure how to handle the other two though.

2. Sep 16, 2012

### Dustinsfl

What I have done so far is:
$\frac{dt}{dr} = 1\Rightarrow t = r + c$ but when $t = 0$, we have $t = r$.

$\frac{dx}{dr} = c(\rho)\Rightarrow x = tu_{\text{max}}\left(1-\frac{2\rho}{\rho_{\text{max}}}\right)+c$ but when $t=0$, we have
$$x = tu_{\text{max}}\left(1-\frac{2\rho}{\rho_{\text{max}}}\right) + x_0.$$

$\frac{d\rho}{dr} = \beta_0\Rightarrow \rho = t\beta_0 + c$

How do I get to
$$\rho(x,t) = t\beta_0 +\rho(x_0,0)$$
and their characteristic?

Last edited: Sep 16, 2012
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