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Deriv. of inverse Cotangent is

  1. Oct 13, 2009 #1
    My notes say the deriv. of inverse Cotangent is -1/(1+x2)

    But when I plot the derivative of this function: 1/Tan-1x
    against -1/(1+x2), I get two different graphs.

    Is Cot-1x not the same thing as 1/Tan-1x ?

  2. jcsd
  3. Oct 13, 2009 #2
    Re: arccot

    They are not the same.

    Let y = cot-1x
    cot y = x
    1/coty = tan y = 1/x
    y = tan-1(1/x)

    cot-1x = tan-1(1/x)
  4. Oct 14, 2009 #3
    Re: arccot

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