1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Derivate of x^p

  1. Oct 8, 2004 #1
    Let y = x^p where p is a natural number. Is it true that
    [tex] \frac{dx^n}{d^ny} = \frac{p!}{(p-n)!} \cdot x^{p-n} [/tex] with the restriction that we define [tex] (-n)! \equiv \infty [/tex] for n=1,2,3... I found this formula and I believe that it is true if we define [tex] (-n)! [/tex] to equal [tex] \infty [/tex].
     
  2. jcsd
  3. Oct 8, 2004 #2

    mathman

    User Avatar
    Science Advisor
    Gold Member

    Your answer is correct, although you wrote the derivative upside down. The definition you used for (-n)! is the standard one.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Derivate of x^p
  1. Derivative of x! (Replies: 6)

  2. L^p derivative (Replies: 1)

  3. Derivative of a^x (Replies: 13)

Loading...