v'=(v-u)/(1-vu/c^2), then dv'=? is it (dv-u)/(1-udv/c^2)?
Related Introductory Physics Homework Help News on Phys.org Conductive nature in crystal structures revealed at magnification of 10 million times Six-wavelength spectroscopy can offer new details of surface of Venus Examination of Theia 456 finds its nearly 500 stars were born at same time
Related Introductory Physics Homework Help News on Phys.org Conductive nature in crystal structures revealed at magnification of 10 million times Six-wavelength spectroscopy can offer new details of surface of Venus Examination of Theia 456 finds its nearly 500 stars were born at same time
Sep 24, 2005 #2 Tom Mattson Staff Emeritus Science Advisor Gold Member 5,500 8 Please don't double post. Also, any homework questions you have should go in the Homework section of PF (at the top of the main page).
Please don't double post. Also, any homework questions you have should go in the Homework section of PF (at the top of the main page).